b^2-12b-160=0

Solution for b^2-12b-160=0 equation:

Simplifying
b2 + -12b + -160 = 0

Reorder the terms:
-160 + -12b + b2 = 0

Solving
-160 + -12b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-8 + -1b)(20 + -1b) = 0

Subproblem 1
Set the factor '(-8 + -1b)' equal to zero and attempt to solve:

Simplifying
-8 + -1b = 0

Solving
-8 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + -1b = 0 + 8

Combine like terms: -8 + 8 = 0
0 + -1b = 0 + 8
-1b = 0 + 8

Combine like terms: 0 + 8 = 8
-1b = 8

Divide each side by '-1'.
b = -8

Simplifying
b = -8
Subproblem 2
Set the factor '(20 + -1b)' equal to zero and attempt to solve:

Simplifying
20 + -1b = 0

Solving
20 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-20' to each side of the equation.
20 + -20 + -1b = 0 + -20

Combine like terms: 20 + -20 = 0
0 + -1b = 0 + -20
-1b = 0 + -20

Combine like terms: 0 + -20 = -20
-1b = -20

Divide each side by '-1'.
b = 20

Simplifying
b = 20
Solution
b = {-8, 20}